If a number is divisible by the sum of its digits, then it will be known as a Harshad Number.

​

For example:

The number 156 is divisible by the sum (12) of its digits (1, 5, 6 ).

​

Some Harshad numbers are 8, 54, 120, etc.

​

In this program, integer value is predefined, we don?t need to put integer value to determine whether the given number is a Harshad number or not by following the algorithm as given below:

below:

​

ALGORITHM:

• STEP 1: START

• STEP 2: SET num = 156, rem =0, sum =0

• STEP 3: DEFINE n

• STEP 4: n = num

• STEP 5: REPEAT STEP 6 to STEP 8 UNTIL (num>0)

• STEP 6: rem =num%10

• STEP 7: sum = sum + rem

• STEP 8: num = num/10

• STEP 9: if(n%sum==0) then PRINT "Yes" else PRINT "No"

• STEP 10: END

num = 156;    

rem = sum = 0;    

     

#Make a copy of num and store it in variable n    

n = num;    

     

#Calculates sum of digits    

while(num > 0):    

    rem = num%10;    

    sum = sum + rem;    

    num = num//10;    

     

#Checks whether the number is divisible by the sum of digits    

if(n%sum == 0):    

    print(str(n) + " is a harshad number");    

else:    

    print(str(n) + " is not a harshad number");    

6)Python program to print all pronic numbers between 1 and 100

​

The pronic number is a product of two consecutive integers of the form: n(n+1).

​

For example:

6 = 2(2+1)= n(n+1),
72 =8(8+1) = n(n+1)

​

Some pronic numbers are: 0, 2, 6, 12, 20, 30, 42, 56 etc.

​

In this program, we need to print all pronic numbers between 1 and 100 by following the algorithm as given below:

​

ALGORITHM:

​

• STEP 1: isPronicNumber() determines whether a given number is the Pronic number or not.

  • Define a boolean variable flag and set its value to false.

  • Use for loop to iterate from 1 to given number and check whether i * (i + 1) is equal to the given number, for any value of i.

  • If a match is found, then set the flag to true, break the loop and returns the value of the flag.

• STEP 2: To display all Pronic numbers between 1 and 100,

  • Start a loop from 1 to 100, and make a call to isPronicNumber() method for each value from 1 to 100.

  • If isPronicNumber() returns true which signifies that number is Pronic, then display that number.

#isPronicNumber() will determine whether a given number is a pronic number or not    

def isPronicNumber(num):    

    flag = False;    

        

    for j in range(1, num+1):    

        #Checks for pronic number by multiplying consecutive numbers    

        if((j*(j+1)) == num):    

            flag = True;    

            break;    

    return flag;    

     

#Displays pronic numbers between 1 and 100    

print("Pronic numbers between 1 and 100: ");    

for i in range(1, 101):    

    if(isPronicNumber(i)):    

        print(i),    

        print(" "),