9)Python program to print the largest element in an array
In this program, we need to find out the largest element present in the array and display it. This can be accomplished by looping through the array from start to end by comparing max with all the elements of an array. If any of element is greater than max, then store a value of the element in max. Initially, max will hold the value of the first element. At the end of the loop, max represents the largest element in the array.
25 11 7 75 56
In the above array, initially, max will hold the value 25. In the 1st iteration, max will be compared with 11, since 11 is less than max. Max will retain its value. In the next iteration, it will be compared to 7, 7 is also less than max, no change will be made to the max. Now, max will be compared to 75. 75 is greater than max so that max will hold the value of 75. Continue this process until the end of the array is reached. At the end of the loop, max will hold the largest element in the array.
ALGORITHM:
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STEP 1: Declare and initialize an array.
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STEP 2: Store first element in variable max.
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STEP 3: Loop through the array from 0 to length of the array and compare the value of max with elements of the array.
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STEP 4: If any element is greater than max, max will hold the value of that element.
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STEP 5: At last, max will hold the largest element in the array.
#Initialize array
arr = [25, 11, 7, 75, 56];
#Initialize max with first element of array.
max = arr[0];
#Loop through the array
for i in range(0, len(arr)):
#Compare elements of array with max
if(arr[i] > max):
max = arr[i];
print("Largest element present in given array: " + str(max));
10)Python program to print the smallest element in an array
In this program, we need to find out the smallest element present in the array. This can be achieved by maintaining a variable min which initially will hold the value of the first element. Loop through the array by comparing the value of min with elements of the array. If any of the element's value is less than min, store the value of the element in the min.
25 11 7 75 56
Consider above array. Initially, min will hold the value 25. In the 1st iteration, min will be compared with 11. Since 11 is less than 25. Min will hold the value 11. In a 2nd iteration, 11 will be compared with 7. Now, 7 is less than 11. So, min will take the value 7. Continue this process until the end of the array is reached. At last, min will hold the smallest value element in the array.
ALGORITHM:
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STEP 1: Declare and initialize an array.
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STEP 2: Store first element in the variable min.
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STEP 3: Loop through the array from 0 to length of the array and compare the value of min with elements of the array.
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STEP 4: If any element is less than min, min will hold the value of that element.
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STEP 5: At last, min will represent the smallest element in the array.
#Initialize array
arr = [25, 11, 7, 75, 56];
#Initialize min with the first element of the array.
min = arr[0];
#Loop through the array
for i in range(0, len(arr)):
#Compare elements of array with min
if(arr[i] < min):
min = arr[i];
print("Smallest element present in given array: " + str(min));